any mathmaticians?

[The-Wolf]

ok I have yet another tank (don't ask where its going, I havn't worked that out yet )

the thing is it is a weird shape (see pic)
I can't find anywhere that can tell me what the gallonage would be,
so I'm asking all you brainy types to work it out for me

excuse the crude drawing, it's my best art work ever

height from bottom to strengthening bars is 22"

EDIT
oh the little bit at the back corner is 6"

 

[steelhealr]

Wolf...you could estimate volume.....consider your tank half of a cube, ie, measure the volume as if you could extend your sides out as a full cube 27 x 27x 22. You could estimate cubic volume by then either dividing that in half, or, by the looks of your drawing 3/5ths or 2/3rds. How much water will fit in a cubic foot of space? SH

PS..do you have MTS?

 

[rdd1952]

I came up with approximately 60 gallon but I hope someone else figures it too. It's been a long time since I've done this.

 

[daza]

I get 204.27 litres = 53.93 gal(US), excluding glass thickness.

I've not double checked what I just did though. There is another shape I didn't think about for my volume calculator, I will add it some time, cheers Wolf!

 

[The-Wolf]

thanks guys;
I would really like a difinitive answer but at least
I can guestimate now for treatments etc.


EDIT
BTW steelhealr
of course I have MTS, dosn't everyone

 

[Corruptor]

A quick model in Solidworks (an engineering program I use at work) gives me all the volume calculations I want. Are those dimensions inside or outside the glass? Either way, the volume runs from 7.03 cubic feet to 7.47 cubic feet, which converts to 52.6 us liquid gallons (43.78 UK gallons, or 199 liters) or 55.8 liquid gallons (46.5 UK galons or 211.5 liters)
http/www.onlineconversion.com/volume.htm

According to the program, the dimensions you listed didn't quite add up, but they're not too far off. Perhaps some were inside and some were outside?



*I'm not a mathmatician, nor do I play one on TV...*

 

[daza]

I just added that tank shape to my Volume Calculator Wolf and it gives very close results to what Corruptor says. To remove the rear corner cutout then I would work that out as a 'corner tank' and deduct that.

edit...spelling.

 

[OohFeeshy]

Why not just get an old jam jar and count how many jam jars full or water you put in to fill it

 

[CathyG]

I make it 221 litres or 49 Imperial Gallons (59 US Gallons)

I took each rectangle that measured 10" x 22" (leaving a 5" square in the corner)
I then took the two triangles that measured 12" x 16" x 22" (the 26" less the 10" square already accounted for with the rectangles)

Therefore:

Rectangles (two of)

10" x 17" x 22" = 3740 cubic inches
10" x 27" x 22" = 5940 cubic inches

Triangles (two of) half base x height (26" - the 10" square allowed for corner for rectangles) for surface area, x depth.

6" x 16" x 22" = 2112 cubic inches x 2 = 4224 cubic inches

I then took the corner:

5" x 5" x 22" = 550 cubic inches. I divided this by 2 to allow for the cut out = 275 cubic inches. We need to deduct this figure off the total.

3740 + 5940 + 4224 - 275 = 13629 cubic inches. or 7.8872 cubic feet.

221.74 Litres
59 US Gallons
49 Imperial Gallons

That is close enough isn't it?

Edit for recalc, I had miscounted the corner due to my poor scribbling to scale )

 

[rdd1952]

I basically broke out the rectangular sides (a 10"x27" regtangle and a 10"x17" rectangle)and then convert the front into 2 triangles (16"x17"x12"). I came up with a total of 13981 cubic inches. The multiplier for ci to gallons is .004329. As I said earlier, I definitely wouldn't make any guarantees on the accuracy of this. Unfortunately, I don't have any software on my PC here at work to draw out what I did. I will try to do it after I get home.

 

[rdd1952]

Here is how I came up with my number:

Rectangle ABCE = 10" x 27" = 270 sq in
Rectangle DEHJ = 10" x 17" = 170 sq in
Triangle CDH = Isosceles Triangle with 2 sides 17". Hypotenuse CH = 24.04
Area = 17" x 17" / 2 = 144.5 sq in.

The Hypotenuse of this triangle brings about a problem. Segments CF & FH would each be 12.02" which is imposible since the hypotenuse of triangles CFG (CG = 12") & FGH (GH = 12") can't be shorter that legs CF & FH. Due to that problem, I would think that the area of those 2 triangle was minimal and that the total of the other 3 areas would be close to the tank volume.

Total area = 270" + 170" + 144.5" = 584.5 sq in
Total volume = 584.5 sq in x 22" = 12859 cu in
1 cu in = .004329 gallon
12859cu in x .004329 galllon = 55.67 gallons

I would think it is somewhere between 56 & 60 gallons.

 

[The-Wolf]

wow, some of you guys just blow my mind

OK I think I'll work on 55 us gal for the purposes of dechlorinator etc.
I'm very greatful to all for taking the time to have a go at this for me.

 

[Opcn]

Your tank doesn't exist, back wall is 22 inches and the outside is 27 inches wich leaves you with 5 inches. (5^2+5^2)^(1/2)=7.07 not 6, if you take super exact measurements from the inside We may be able to get even more acurate measurements, personally I garauntee all my calculations to 6 decimal places.