Maths Guru Needed

[The-Wolf]

hi all
here is the problem
I have a 100ml of 30% solution A I need 1 litre of a 10% solution C
(the 30% solution can not be made into a 100% solution)
I will be adding distilled B (de-ionised) water to the 30% solution

how much B to how much A to achieve C

 

[Matty P]

Thats not my department!

 

[mark7616]

200ml of water then do it to 3 further bottles.

 

[JamieBailie]

Thats not my department!

So don't spam the topic.

200ml

 

[-germ-]

But surely 200 ml of RO water plus 100ml of solution makes 300ml?
Not a litre as required?
If no one has it by the time she's awake my GF will know for certain....

 

[LakeyGal]

If that makes 300ml of a 10% solution I think you need 3 more bottles?

 

[mark7616]

yep thats what I had in mind but didnt like the idea so edited the post.

 

[SuperColey1]

It cant be done

If you only have 100ml of 30% then to get 1 litre of anything then you will need to add 900ml to get 1 litre therefore you don't have enough 30% to make the mix.

You would need 333ml of 30% solution and mix with 666ml of DI water to get 1 litre of 10% solutions and as you only have 100ml you can only make 300ml total by adding 200ml DI water to it.

Just read above post and I am repeating . lol in a much overcomplicated way too. I'm learning Germ so her is my new reply

YOU CAN'T

Lol

Andy

 

[The-Wolf]

ok so let me get this correct
if I add 300ml water to 100ml of the 30% that will make 900ml at 10%,
I think 900ml will suffice for what I need

all will be revealed at a later date as to why I need this and what the solution is

 

[SuperColey1]

No that is wrong

If 100ml of solution 30% of a substance then that makes 30ml

added to 200ml of DI =

300ml soplution which still contains the original 30ml of substance whic = 10%

Andy

Also 300+100 never makes 900 anyway. lol

 

[iSnail]

ok so let me get this correct
if I add 300ml water to 100ml of the 30% that will make 900ml at 10%,
I think 900ml will suffice for what I need

all will be revealed at a later date as to why I need this and what the solution is

Add 200ml water to your 100ml 30% solution will make 300ml new solution at 10% concentration

100ml solution A + 200ml B = 300ml solution C

so you are still short of 700ml of solution C

 

[The-Wolf]

arggggg, I hate maths

ok forget the volumes I have stated above
I need to know how much water to add to what volume of a 30% solution to make 1ltr of a 10% solution
I can buy the 30% solution in 100ml or 250ml if that helps

 

[Jabba]

arggggg, I hate maths

ok forget the volumes I have stated above
I need to know how much water to add to what volume of a 30% solution to make 1ltr of a 10% solution
I can buy the 30% solution in 100ml or 250ml if that helps

Based on that you can't, the dilution up to 1 litre will be less than 30% because of your starting volume.

Simple divide the initial %age by the required %age then multiply the initial volume of which it is a percentage by the result. i.e. (30/10)*250 = 750ml

Well 250ml will make 750ml and 100ml will make 300ml - add the two thats 1050ml - tad over a litre will that do ?

PS to prove this theorem - 30% of 250 = 75, 10% of 750 = 75

 

[backtotropical]

Ok. Your final solution is to be 1 litre with 10% saturation.

Therefore you need 100ml of saturation liquid (whatever that may be).

Your basic solution is 30% saturation, so 100ml / 30 x 100 = 333.33ml of basic solution required. This gives 100ml of saturation as required.

Top this up with 666.67ml of water (or whatever your dilutant is) and you have 1 litre with a 10% saturation.

Summary

333.33ml basic solution
666.67ml dilutant



Do i get a prize??? LOL.

 

[loachman]

arggggg, I hate maths

ok forget the volumes I have stated above
I need to know how much water to add to what volume of a 30% solution to make 1ltr of a 10% solution
I can buy the 30% solution in 100ml or 250ml if that helps

333 ml of the 30%, add RO water to make 1 liter (667 ml of RO water).